SQL查询-范围查询(区间查询)

--范围查询（区间查询）
--in()
--查询年龄为18,28，38的人   select *from student where age=18 or age=28 or age=38;
select *from student where age in(18,28,38);
--not in
--查询年龄为18,28，38的人   select *from student where not (age=18 or age=28 or age=38);
select *from student where age not in (18,28,38);
--between...and...
--查询12-18的人
select *from student where age between 12 and 18;
-- not between...and...
-- 查询年龄不在12-18的人
select *from student where age not between 12 and 18;
-- 失败select *from student where age not (between 12 and 18);

--判断空
-- is null
-- 判断年龄是否为空
select *from student where age is null;
-- is not NULL
-- 判断年龄不为空
select *from student where age is not null;

(资源库 www.zyku.net)

原文链接：https://www.cnblogs.com/jum-bolg/p/11235427.html